Please help me with this physics 12 question? easy 10 points!!! >.<
Favorites|Homepage
Subscriptions | sitemap
HOME > Physics > Please help me with this physics 12 question? easy 10 points!!! >.<

Please help me with this physics 12 question? easy 10 points!!! >.<

[From: ] [author: ] [Date: 11-05-25] [Hit: ]
c) well you have the answer to b), just multiply how many kWhours you used (72kWh) times the price per hour ( $0.work is defined as energy per unit time, so one Watt = 1 joule per second,......
When you pay your electricity bill, you are charged not for power but for the energy used. The unit for measuring the energy used is the kilowatthour (kWh).
(a) How many joules are there in one kWh?
(b) How much energy, in kWh, does a 400-W TV set use in a month (30 days), if it is used an average of 6.0 h each day?
(c) If electrical energy costs $0.06 /kWh, what will it cost you to operate the TV set for one month?

the answers are: (a) 3.6 x 106 J (b) 72 kWh (c) $4.32

i need to know how to do this question, please explain each step thankyou so much!!! =D

-
1 kilowatt hour = 3 600 000 joules (or 3.6 x 10^6), so really you just multiply
b) 400W times 30 days of 6 hours each = 400*30*6 = 72000 kWH (just multiply kW times hour to get kW hour lol )
* SORRY in case you read this part already, one correction, 72 kWh OR 72000 Wh, sorry not 7200kWh, the extra k is a mistake!

c) well you have the answer to b), just multiply how many kWhours you used (72kWh) times the price per hour ( $0.06)

sorry in hindsight I didn't explain part a properly :
work is defined as energy per unit time, so one Watt = 1 joule per second, therefore 1 kW = 1000 joules per second
now 1 kWh = 1 kW times 1 hour (or 3600 seconds) = 1000 joules per second times 3600 seconds = 3600000 joules
1
keywords: with,lt,this,Please,gt,12,points,me,easy,10,physics,question,help,Please help me with this physics 12 question? easy 10 points!!! >.<
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .