A 1.83 kg mass is on a 20 degree slope attatched to a pulley with a 2kg mass on the other side. Static coefficient of friction = 0.80 and kinetic coefficient of friction = 0.50. The string and pulley are massless and frictionless. What acceleration will the 1.83 kg mass have if it begins to be pulled up the incline?
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Hello
The net force is = m1g - m2g*sin20 - μm2gcos20 (with m1 = 2 kg, m2 = 1.83 kg, μ = 0.5)
net force = 2*9.81 - 1.83*9.81*sin20 - 0.5*1.83*9.81*cos20
and the acceleration = net force/ total mass
a = (2*9.81 - 1.83*9.81*sin20 - 0.5*1.83*9.81*cos20)/(2 + 1.83)
Regards
The net force is = m1g - m2g*sin20 - μm2gcos20 (with m1 = 2 kg, m2 = 1.83 kg, μ = 0.5)
net force = 2*9.81 - 1.83*9.81*sin20 - 0.5*1.83*9.81*cos20
and the acceleration = net force/ total mass
a = (2*9.81 - 1.83*9.81*sin20 - 0.5*1.83*9.81*cos20)/(2 + 1.83)
Regards