Physics torque and forces question (involves a second class lever)

A wheel barrow is 2,0 m long. A 50.0 kg pile of dirt is resting .5 m from the wheel.

What force must be applied to raise the dirt?
What is the mechanical advantage of the wheel barrow?
If the dirt is raised to be 10.0 cm, what distance did the force act?

(50 x 9.8) = 490N. weight.
(490 x .5) /2 = 122.5N. force on the ends of the handles.

MA = (2/.5) = 4.

40cm. (dirt's 10cm. x MA).