A car of mass 1900kg is traveling east at a speed of 24 m/s along a horizontal roadway. When its brakes are applied, the car stops in 7.1 s. What is the average horizontal force exerted on the car while it is braking?
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Distance to stop = 1/2 (vt), = 85.2m.
Acceleration = (v^2/2d) = 3.38m/sec^2, west.
Force = (ma) = 1900 x 3.38, = 6,422N. applied west.
Acceleration = (v^2/2d) = 3.38m/sec^2, west.
Force = (ma) = 1900 x 3.38, = 6,422N. applied west.
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ok well... F = ma a = (vf - vi)/ (t)
vf = 0
vi = 24m/s
t = 7.1 s a = -3.38
m = 1900kg F = 6422 N technically -6422 N but all the (-) implies in this case is that the force is being used to stop the object the was in motion (in this case the car)
vf = 0
vi = 24m/s
t = 7.1 s a = -3.38
m = 1900kg F = 6422 N technically -6422 N but all the (-) implies in this case is that the force is being used to stop the object the was in motion (in this case the car)