Moment of inertia question
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Moment of inertia question

[From: ] [author: ] [Date: 11-07-01] [Hit: ]
10*.40² = .......
Three 0.10 kg balls are connected by light rods to form an equilateral triangle with a side length of 0.40m.
What is the moment of inertia of this triangle about an axis perpendicular to its plane and passing through one of the balls? Express answer in kg/m^2

Thanks

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I = 2*m*R² = 2*.10*.40² = .032 kg∙m²

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46

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this is what school is for
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