A block of mass 0.18 kg is attached to a spring of force constant 2 N/m.The coefficient of friction between the block and the floor is 0.1.Initially the spring is unstretched and the block is at rest.An impulse is given to the block towards trhe spring to compress it.The block sldes a distance of 0.06 m and comes to rest for the first time.The initial velocity of block is N/10 m/s , what is N ?
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Use the work-kinetic energy theorem here.
Loss in kinetic energy = -0.5 * m * V^2
Work done by friction = -μ*m*g*x
Work done by Spring force = -0.5*k*x^2
so ..... by work-kinetic energy theorem
-0.5 * m * V^2=-μ*m*g*x+-0.5*k*x^2
After substituting the following values k=2 N/m, V=N/10 m/s , μ=0.1 , x=0.06 m , m=0.18 kg in the above equation , you will get the answer N=4
Thanks.
Loss in kinetic energy = -0.5 * m * V^2
Work done by friction = -μ*m*g*x
Work done by Spring force = -0.5*k*x^2
so ..... by work-kinetic energy theorem
-0.5 * m * V^2=-μ*m*g*x+-0.5*k*x^2
After substituting the following values k=2 N/m, V=N/10 m/s , μ=0.1 , x=0.06 m , m=0.18 kg in the above equation , you will get the answer N=4
Thanks.