Physics--- Is this the correct answer

Coefficient of static friction between tires and the road is 0.3. If the car takes a curve with r=10 m, what is the max velocity the car can travel without skidding?

Answer:
Coefficient= Ffriction/ Fnormal.
Fnormal = Fgravity = 98 N. (Assuming mass is 10... It cancels in the end of the problem).
So, Ff= 29.4 N.

Ff= Centripetal acceleration = m . (v^2/r/).
v^2= 29.4 /10 X 10 = 29.4.
V=5.42 m/s2.


Is this right?

There is one simple formula to calculate the max velocity of car in such cases

V (max) = sqrt(ugR)

where u = coefficient of friction
R = Rad of curve

So, acc. to this eqn,

V (max) = sqrt(0.3*9.8*10)

V (max) = sqrt(29.4)

Ans = 5.42 m/s

Yes your ans is right except that the unit of velocity is m/s not m/s2

idk, I aint taking that class.