Prove 1Ω*1F=1s . . . . .

I've made some calculations and I think Ω equals J*s/C*C ,but I dunno what a Faraday means. :/

A farad is a unit of capacitance. The ability to store charge.
1 farad = 1 coulomb / volt.
And of course a volt is a joule / coulomb

From here you should be able to complete your problem easily.

A Faraday and a Farad (the unit which this equation refers to) are different units of measure. Faradays measure the magnitude of an electric charge per mole of electrons and a Farad is a measure of capacitance.

I think this previous y!a question will help you understand the concept behind it using math:

http://answers.yahoo.com/question/index?…

F is farad, a unit of electrical capacitance. 1 F = 1 Coulomb/ 1 volt and 1 Coulomb is the unit of charge and 1 Coulomb = 1 Ampere x 1 second

1 ohm = 1 volt /1 ampere

so 1 ohm x 1 farad = 1 volt/1 amp x 1 amp x 1 s / 1 volt = 1s

so ohm x farad = seconds