How many grams of Ca and Cl2 from decomposing 333g of CaCl2

thanks in advance!!! i would greatly appreciate help! ;)

well the equation is CaCl2 -> Ca + Cl2

333gCaCl2 x 1mol CaCl2/110.98 = 3 moles either Ca or Cl2

3 moles x 40.08(molars mass calcium) = 120.24 Ca
3 moles x 70.9 (molar mass Cl2) = 212.7g Cl2