how to calculate % current efficiency?
In process trials 50g of zinc was produced from solution using a current of 2 amps for 24 hours. Calculate the current efficiency
In process trials 50g of zinc was produced from solution using a current of 2 amps for 24 hours. Calculate the current efficiency
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No. of coulombs passed = 2A x 24hrx60minx60sec = 172800C
Zn2+ + 2e- = Zn
So 2 moles (2 faraday= 2 x 96500C = 193000C) of electricity is required for this process.
Efficiency = (193000-172800/193000 X 100 = 10.47%
Zn2+ + 2e- = Zn
So 2 moles (2 faraday= 2 x 96500C = 193000C) of electricity is required for this process.
Efficiency = (193000-172800/193000 X 100 = 10.47%
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thank you very much - just a couple of questions to understand this more - why is the 50g zinc not used in the equation? and why do you have to use the minutes and seconds when you have hours already? cheers
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