1 chemistry question plz!?!

balance:
_Fe +_HC2H3O2 ---->_Fe(C2H3O2)3 +_H2

_Fe +_HC2H3O2 ---->_Fe(C2H3O2)3 +_H2

Since Hydrogen goes from 1 to 2 and C2H3O2 goes from 1 to 3, the common denominator is 2*3 which is 6. Multiply HC2H3O2 by 6

_Fe + 6HC2H3O2 ----> Fe(C2H3O2)3 +H2

Now multply the H2 by 3 and the C2H3O2 by 2 on the right.

_Fe +6HC2H3O2 ---->2Fe(C2H3O2)3 + 3H2

All that is out of balance is the Fe which requires a 2.

Answer
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2Fe +6HC2H3O2 ---->2Fe(C2H3O2)3 +3H2

It would be: _2_Fe+_6_HC2H3O2 ---> _2_Fe(C2H3O2)3+_3_H2 (So in order you would put 2, 6, 2, 3 in the blanks). Hope this helps ;)

by this reaction the product will be:
2Fe + 6HC2H3O2 ---->2Fe(C2H3O2)3 + 3H2

2Fe + 6HC2H3O2 ---->2Fe(C2H3O2)3 + 3H2