given
0.142 mol Argon
volume of Argon=834 ml Argon
Pressure of Argon=4.83
wanted: the temperature of the Ar gas sample on the celsius scale?
0.142 mol Argon
volume of Argon=834 ml Argon
Pressure of Argon=4.83
wanted: the temperature of the Ar gas sample on the celsius scale?

PV = nRT
(4.83 probably atmospheres) (0.834 Litres) = 0.142 mol (0.08206 Latm/molK) (T)
T = 345.70 Kelvin
but rounded to 3 sig figs would be
T = 346 Kelvin
346 Kelvin  273 = 73 Celsius
you can email me if the pressure was not atm's
(4.83 probably atmospheres) (0.834 Litres) = 0.142 mol (0.08206 Latm/molK) (T)
T = 345.70 Kelvin
but rounded to 3 sig figs would be
T = 346 Kelvin
346 Kelvin  273 = 73 Celsius
you can email me if the pressure was not atm's