Please help me with some questions about indices? 10 points :D

- What is the square root of '4x' ?
- Can 4z^-3 be written as 4/z^3 ?

Please explain how to solve this question for me :
( 4x^3/2) / (2x^1/2)

Thanks in advance!

1. On this one you have to make the SQRT of each value. "root" of 4 is 2, and "root" of x is x^0.5. so the final answer is 2x^0.5

2. It is possible to write it that way. Example: x^-2 is equivalent to 1/x^2.

3. (4x^(3/2)) / ( 2x^(1/2))
divide 4/2 = 2
*It's also important to point that the division of two exponential values with the same base equals the (BASE^(difference between exponents). Therefore:

2x^( (3/2) - (1/2) )
2x.

Hello cookie, (1)square root of 4x is 2 multiplied by squareroot x. (2)Yes, 4/z'3 can be written. (3)4x'(3/2) /2x'(1/2) =2x'(3/2) /x'(1/2) =2x'(3/2-1/2) =2x'1=2x(Ans.)

1.2x^1/2
2.no

(4x^3/2)/(2x^1/2)
=4/2*x^3/2-1/2
=2*x^1
=2X is the answer

regards,

Lokesh

2 'root' x [2 outside the square root, x under the square root]

and yes

1.2x^1/2
2.no

(4x^3/2)/(2x^1/2)
=4/2*x^3/2-1/2
=2*x^1
=2X