[From: ] [author: ] [Date: 11-05-20] [Hit: ]
On this one you have to make the SQRT of each value. root of 4 is 2, and root of x is x^0.5. so the final answer is 2x^0.2.......
- What is the square root of '4x' ?
- Can 4z^-3 be written as 4/z^3 ?

Please explain how to solve this question for me :
( 4x^3/2) / (2x^1/2)

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1. On this one you have to make the SQRT of each value. "root" of 4 is 2, and "root" of x is x^0.5. so the final answer is 2x^0.5

2. It is possible to write it that way. Example: x^-2 is equivalent to 1/x^2.

3. (4x^(3/2)) / ( 2x^(1/2))
divide 4/2 = 2
*It's also important to point that the division of two exponential values with the same base equals the (BASE^(difference between exponents). Therefore:

2x^( (3/2) - (1/2) )
2x.

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Hello cookie, (1)square root of 4x is 2 multiplied by squareroot x. (2)Yes, 4/z'3 can be written. (3)4x'(3/2) /2x'(1/2) =2x'(3/2) /x'(1/2) =2x'(3/2-1/2) =2x'1=2x(Ans.)

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1.2x^1/2
2.no

(4x^3/2)/(2x^1/2)
=4/2*x^3/2-1/2
=2*x^1

regards,

Lokesh

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2 'root' x [2 outside the square root, x under the square root]

and yes

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1.2x^1/2
2.no

(4x^3/2)/(2x^1/2)
=4/2*x^3/2-1/2
=2*x^1
=2X
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