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3.45 moles of hydrogen gas are collected at 1.05 atm and 300.0 K. the sample is cooled to 145.0 K. what is the new pressure?
a 5.0L volume of gas has a pressure of 1.4 atm. what pressure will this same gas sample have if the volume is doubled?
a hot air balloon holds 5,000.0 L of gas when completely inflated. the inflated temperature of the gas is 650K. what is the volume when the gas in this balloon occupy at 298 K (normal room temperature)?
i also though you used combined gas laws but am i wrong?
PV/T=k
V1P1T2=V2P2T1
P1V1/T1=P2V2/T2
i dont even understand how those go X[
3.45 moles of hydrogen gas are collected at 1.05 atm and 300.0 K. the sample is cooled to 145.0 K. what is the new pressure?
a 5.0L volume of gas has a pressure of 1.4 atm. what pressure will this same gas sample have if the volume is doubled?
a hot air balloon holds 5,000.0 L of gas when completely inflated. the inflated temperature of the gas is 650K. what is the volume when the gas in this balloon occupy at 298 K (normal room temperature)?
i also though you used combined gas laws but am i wrong?
PV/T=k
V1P1T2=V2P2T1
P1V1/T1=P2V2/T2
i dont even understand how those go X[
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You are correct about using the combined gas laws.
1) For the first question since pressure and temperature are the only things changing:
P1/T1=P2/T2
so: P2=(P1)(T2)/(T1)=(1.05atm)(145.0K)/(300K…
Kelvin cancel out and you are left with atm so you know the set up is correct and the answer should be: 0.5075 atm
2) For the second ? volume and pressure are changing while the others are constant so you just focus on volume and perssure:
P1V1=P2V2 rearrange to solve for P2
P2=(P1)(V1)/(V2)=(1.4atm)(5.0L)/(10L) Liters cancel out and you are left with atm.
P2=0.7atm
3)For this one you are only dealing with volume and temperature, so only use volume and temperature because the other factors are constant.
V1/T1=V2/T2 rearrange to solve for V2 you get
V2=(V1)(T2)/(T1)=(5000L)(298K)/(650K) Kelvin cancel out and you are left with unit of Liters
V2=2292.3076L
1) For the first question since pressure and temperature are the only things changing:
P1/T1=P2/T2
so: P2=(P1)(T2)/(T1)=(1.05atm)(145.0K)/(300K…
Kelvin cancel out and you are left with atm so you know the set up is correct and the answer should be: 0.5075 atm
2) For the second ? volume and pressure are changing while the others are constant so you just focus on volume and perssure:
P1V1=P2V2 rearrange to solve for P2
P2=(P1)(V1)/(V2)=(1.4atm)(5.0L)/(10L) Liters cancel out and you are left with atm.
P2=0.7atm
3)For this one you are only dealing with volume and temperature, so only use volume and temperature because the other factors are constant.
V1/T1=V2/T2 rearrange to solve for V2 you get
V2=(V1)(T2)/(T1)=(5000L)(298K)/(650K) Kelvin cancel out and you are left with unit of Liters
V2=2292.3076L