Adding and Subtracting Polynomials

Can you answer these for me please? If you would, you would be a Life saver!!! :3 (There are exponents, the numbers outside of the parenthesis are them)
(g-12)2
(4x+2)2
(4x-2)2
(3-5x)2
(t+8)(t-8)
(c-d)(c+d)
(5x+2)(5x-2)
(4x+3y)(4x-3y)


THANKS A DOZEN !!!

♥♦♣♠
you need to multiply the contents of one parenthesis
to each of the contents of the other parenthesis.

(g-12)2
( g - 12 ) ² = ( g - 12 ) ( g - 12 )
= ( g ) ( g ) + ( g ) ( -12 ) + ( -12 ) ( g ) + ( -12 ) ( -12 )
= g ² - 12g - 12g + 144
= g ² - 24g + 144
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(4x+2)2
( 4x +2 ) ² = ( 4x + 2 ) ( 4x + 2 )
= ( 4x ) ( 4x ) + ( 4x ) ( 2 ) + ( 2 ) ( 4x ) + ( 2 ) ( 2 )
= 16x ² + 8x + 8x + 4
= 16x ² + 16x + 4
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(4x-2)2
( 4x - 2 ) ² = ( 4x - 2 ) ( 4x - 2 )
= ( 4x ) ( 4x ) + ( 4x ) ( -2 ) + ( -2 ) ( 4x ) + ( -2 ) ( -2 )
= 16x ² - 8x - 8x + 4
= 16x ² - 16x + 4
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(3-5x)2
( 3 - 5x ) ² = ( 3 - 5x ) ( 3 - 5x )
= ( 3 ) ( 3 ) + ( -5x ) ( 3 ) + ( -5x ) ( 3 ) + ( -5x ) ( -5x )
= 9 - 15x - 15x + 25x ²
= 9 - 30x + 25x ²
= 25x ² - 30x + 9
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(t+8)(t-8)
= ( t ) ( t ) + ( t ) ( -8 ) + ( 8 ) ( t ) + ( 8 ) ( -8 )
= t ² - 8t + 8t - 64
= t ² - 64
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(c-d)(c+d)
= ( c ) ( c ) + ( c ) ( d ) + ( -d ) ( c ) + ( -d ) ( d )
= c ² + cd - cd - d ²
= c ² - d ²
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(5x+2)(5x-2)
= ( 5x + 2 ) ( 5x - 2 )
= ( 5x ) ( 5x ) + ( 5x ) ( -2 ) + ( 2 ) ( 5x ) + ( 2 ) ( -2 )
= 25x ² - 10x + 10x - 4
= 25x ² - 4
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(4x+3y)(4x-3y)
= ( 4x ) ( 4x ) + ( 4x ) ( -3y ) + ( 3y ) ( 4x ) + ( 3y ) ( -3y )
= 16x ² - 12x + 12x - 9y ²
= 16x ² - 9y ²
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I'm gonna tell u how to solve by making just 3 ones and u conclude the method to do them by urself
so
(g - 12)*2
then
2*g - 2*12
2g - 24