Solve the following system for x and y.
2x  8y = 28
4x+ 5y = 7
2x  8y = 28
4x+ 5y = 7

Let 2x  8y = 28 be equation 1
and 4x + 5y = 7 be equation 2
Now,by multiplying equation 1 by 2,we get
4x  16y = 56.Let it be equation 3.
Thereafter,by subtracting equation 2 by equation 3,we get
(4x  16y)  (4x + 5y) = 56  (7)
which simplifies to y = 3.
Further,putting y = 3 in any of the equation 1 or 2,we get x = 2.
Hence,x = 2 and y = 3 is the required solution of the given system of equations.
HoPe YoU uNdErStOoD..... ;)
and 4x + 5y = 7 be equation 2
Now,by multiplying equation 1 by 2,we get
4x  16y = 56.Let it be equation 3.
Thereafter,by subtracting equation 2 by equation 3,we get
(4x  16y)  (4x + 5y) = 56  (7)
which simplifies to y = 3.
Further,putting y = 3 in any of the equation 1 or 2,we get x = 2.
Hence,x = 2 and y = 3 is the required solution of the given system of equations.
HoPe YoU uNdErStOoD..... ;)

Solve the first given equation for x:
x = 4y + 14
Substitute this value for x into the second given equation:
4(4y + 14) + 5y = 7
Expand:
16y + 56 + 5y = 7
Combine like terms:
21y = 63
Divide by 21:
y = 3
Substitute this value for y into x = 4y + 14:
x = 4(3) + 14 = 2
x = 4y + 14
Substitute this value for x into the second given equation:
4(4y + 14) + 5y = 7
Expand:
16y + 56 + 5y = 7
Combine like terms:
21y = 63
Divide by 21:
y = 3
Substitute this value for y into x = 4y + 14:
x = 4(3) + 14 = 2

x = 2, y = 3