Can someone help with math homework
HOME > Mathematics > Can someone help with math homework

# Can someone help with math homework

[From: ] [author: ] [Date: 11-05-25] [Hit: ]
Thereafter,by subtracting equation 2 by equation 3,which simplifies to y = -3.Further,putting y = -3 in any of the equation 1 or 2,we get x = 2.......
Solve the following system for x and y.

2x - 8y = 28
4x+ 5y = -7

-
Let 2x - 8y = 28 be equation 1
and 4x + 5y = -7 be equation 2

Now,by multiplying equation 1 by 2,we get
4x - 16y = 56.Let it be equation 3.

Thereafter,by subtracting equation 2 by equation 3,we get
(4x - 16y) - (4x + 5y) = 56 - (-7)

which simplifies to y = -3.

Further,putting y = -3 in any of the equation 1 or 2,we get x = 2.

Hence,x = 2 and y = -3 is the required solution of the given system of equations.

HoPe YoU uNdErStOoD..... ;)

-
Solve the first given equation for x:
x = 4y + 14
Substitute this value for x into the second given equation:
4(4y + 14) + 5y = -7
Expand:
16y + 56 + 5y = -7
Combine like terms:
21y = -63
Divide by 21:
y = -3
Substitute this value for y into x = 4y + 14:
x = 4(-3) + 14 = 2

-
x = 2, y = -3
1
keywords: help,homework,Can,with,math,someone,Can someone help with math homework
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .