Simplifying Radicals - 10 Pts for Explanation
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# Simplifying Radicals - 10 Pts for Explanation

[From: ] [author: ] [Date: 11-07-07] [Hit: ]
which simplifies to 3 radical 2. What am I doing wrong?For the second row, I do 6 + 2 radical 6, which is 8 radical 6 over 6. I simplify this to4 radical 6 over 3.......
http://img843.imageshack.us/img843/2748/…

When I do the first row, I add 10 to 5 radical 2, so I get 15 radical 2 over 5, which simplifies to 3 radical 2. What am I doing wrong?

For the second row, I do 6 + 2 radical 6, which is 8 radical 6 over 6. I simplify this to 4 radical 6 over 3.
How does this simplification work?

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You've made the exact same problem for the second question, you can't add the radical term with the integer term.

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In the first one (10+5(2)^.5)/5 its the same as writing (10/5)+ (5(x^.5)/5) here all fractions have exact results so you get 2+(x^.5) right?.. whats different on the second one?…

(6/6)+(2*(x^.5)/6)= 1+(x^.5)/3= (3+(x^.5))/3