Can someone Factor this please
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Can someone Factor this please

[From: ] [author: ] [Date: 11-08-31] [Hit: ]
.y = 2(x+3)(x-1/2) OK!...y = 2( x^2 -x/2 +3x -3/2) = 2x^2 -x +6x -3 = 2x^2 +5x -3 OK!......
2x^2+5x-3

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(2x -1 )(x + 3)

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The formula to factor a quadratic function y = ax^2 + bx + c is:

Find the roots... x1 and x1 and write: y = a(x-x1)(x-x2)

In you case the roots are -3 and 1/2 then we factor so:

y = 2(x+3)(x-1/2) OK! ... To verify just multiply:

y = 2( x^2 -x/2 +3x -3/2) = 2x^2 -x +6x -3 = 2x^2 +5x -3 OK!

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2x^2-6x+x-3
2x(x-3)+1(x-3)
(2x+1)(x-3)

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(2x -1)(x + 3)
1
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