√((4-x)/(x^2-4))
The entire fraction is in the radical.
How do I find the domain & range of this.? I'm lost in the dark on this. Thanks to anyone who helps.
The entire fraction is in the radical.
How do I find the domain & range of this.? I'm lost in the dark on this. Thanks to anyone who helps.
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This is algebra
√((4-x)/(x^2-4))
for it to have real solutions, the ((4-x)/(x^2-4))
must be ≥ 0, or 4-x ≥ 0
or 4 ≥ x
but for the
((4-x)/(x^2-4)) to be defined, the denominator must NOT = 0
or x² # 4. x# ±2
the domain is the combination of the two conditions you set.
all real numbers ≤ 4 excluding ±2
so on the number line you should draw two tiny circles at =2 and -2, and then mark your domain.
√((4-x)/(x^2-4))
for it to have real solutions, the ((4-x)/(x^2-4))
must be ≥ 0, or 4-x ≥ 0
or 4 ≥ x
but for the
((4-x)/(x^2-4)) to be defined, the denominator must NOT = 0
or x² # 4. x# ±2
the domain is the combination of the two conditions you set.
all real numbers ≤ 4 excluding ±2
so on the number line you should draw two tiny circles at =2 and -2, and then mark your domain.