How do I solve these

Can someone help me solve these I don't need the answer just the method
A)5- 3x/2=4
B)-3(4+x)/2=-9
C)4(1-3x)/5=8

I might need some more help later with new equations

A) 5 - 3x/2 = 4.

Multiply both sides by 2, giving
10 - 3x = 8.
Add 3x to both sides, giving
10 = 3x + 8.
Subtract 8 from both sides, giving
3x = 2.
Divide both sides by 3, giving
x = 2/3.


B) -3(4+x)/2 = -9.

Multiply both sides by 2, giving
-3(4+x) = -18.
Divide both sides by -3, giving
4 + x = 6.
Subtract 4 from both sides, giving
x = 2.


C) 4(1-3x)/5 = 8.

Multiply both sides by 5, giving
4(1-3x) = 40.
Divide both sides by 4, giving
1 - 3x = 10.
Subtract 1 from both sides, giving
-3x = 9.
Divide both sides by -3, giving
x = -3.

thx really help*

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A) 5 - 3x/2 = 4
-3x/2 = 4/5
-3x = 8/5
x = -8/15

B) -3(4+x)/2 = -9
-3(4+x) = -18
4+x = 6
x = 2

C) 4(1-3x)/5 = 8
4(1-3x) = 40
1-3x = 10
-3x = 9
x = -3

A) 5-3x/2=4....
5-3x=8
-3x=3
x=-1
B) -3(4+x)/2=9
-3(4+x)=18
4+x=-6
x=-10
C)4(1-3x)/5=8
4(1-3x)=40
1-3x=10
-3x=9
x=-3