What is the quotient: (6x^3 + 23x^2 + 10x – 25) ÷ (2x + 5)

You can use synthetic division,
-2.5|6 23 10 -25
........-15 -20 25
--------------------------
......6 8 -10 |0
So, (6x^3 + 23x^2 + 10x – 25) ÷ (2x + 5) = (6x^3 + 23x^2 + 10x – 25) ÷ 2(x + 2.5) = 3x^2 + 4x - 5

Hi there.

..................________3x^2____+ __4x____-10_____________________________…
2x + 5| 6x^3 +23x^2 +10x -25
| 6x^3 + 15x^2
_________________
8x^2 +10x -25
8x^2 + 20x
____________________
-20x -25
-20x +50
_____________
-75


The quotient is 3x^2+4x-10 and the remainder is -75.

3x^2+4x-5

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