Can someone help me with geometric sequence

Need someone to do this step by step so i could use it as an example for my other questions

Find the nth term of the geometric sequence

a1=4, r=1/2, n=10



10 points for best answer :]

generally, in a geometric sequence with common ratio r,

a(sub)n = a(sub1)*r^(n-1)

a(sub)10 = 4*(1/2)^9

a(sub)10 = 4 / 512

a(sub)10 = 1 / 128

It's geometric, so you're multiplying by 1/2 each time.

a_1 = 4

a_n = 4*[(1/2)^(n-1)]

nth term = a1 * r^(n-1)

a10 = 4 * (1/2)^(9)

a10 = 4*1/512 = 4/512 = 1/128

Jen