Simplify (tanx-cotx)sinxcosx+2cos^2x
Need help!
Need help!
-
(tanx-cotx)sinxcosx+2cos^2x
[(sinx/cosx)-cosx/sinx)]sinxcosx+2cos^…
taking LCM,we have;
[(sin^2x - cos^2x)/sinxcosx]sinxcosx + 2cos^2x
sinxcosx cancels sinxcosx and we have,
sin^2x - cos^2x + 2cos^2x
= sin^2x + cos^2x = 1.
[(sinx/cosx)-cosx/sinx)]sinxcosx+2cos^…
taking LCM,we have;
[(sin^2x - cos^2x)/sinxcosx]sinxcosx + 2cos^2x
sinxcosx cancels sinxcosx and we have,
sin^2x - cos^2x + 2cos^2x
= sin^2x + cos^2x = 1.