Help With Some Probability

In the first nine months of a year, airline consumer complaints were 0.98 per 100,000 passengers.

a. what is the probability that in the next 100,000 passengers, the airline will have no complaints?

b. what is the probability that in the next 100,000 passengers, the airline will have at least one complaint?

c. what is the probability that in the next 100,000 passengers the airline will have at least two complaints?

use poisson distribution with mean m = 0.98, and formula
P[x] = e^-m *m^x /x!

a. P[0] = e^-0.98 = 0.3753 <-------

b. P[≥1] = 1 - P[0] = 0.6247 <------

c. P[≥2] = 1 - P[<2] = 1 - 0.7431 = 0.2569 <-----

I am confused