Find all solutions of the equation in the interval [0,2pi] for 3cot^2 x-1=0

Write your answer in radians in terms of .
If there is more than one solution, separate them with commas.

*Note: the 2 isn't 2x..3 cot to the power of 2* x minus 1 = 0* ANSWER must be in radians

3 cot^2 x - 1 = 0
3 cot^2 x = 1
cot^2 x = 1/3
cot x = ± 1/√3

x = π/3, 2π/3, 4π/3, 5π/3

cot^2 x = 1/3
tan^2 x = 3
tan x = ±√3
x = π/3, 2π/3, 4π/3, 5π/3


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3cot^2x - 1 = 0
cot^2x = 1/3
cotx = 1/√3 or cotx = -1/√3
x = pi/3 or x = 4pi/3 or x = 2pi/3 or x = 5pi/3