A 1.5-kg copper block is given an initial speed of 3.0 m/s on a rough horizontal surface. Because of friction
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A 1.5-kg copper block is given an initial speed of 3.0 m/s on a rough horizontal surface. Because of friction

[From: ] [author: ] [Date: 11-05-14] [Hit: ]
b) What happens to the remaining energy?dT = .80*½*1.5*3.0²/(1.Remaining energy heats the surface and surrounding air.......
the block final comes to rest.
a) If the block absorbs 80% if its initial kinetic energy as internal energy, calculate its increase in temperature.

b) What happens to the remaining energy?

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a)
dT = H/(M*C) where C is the specific heat of copper in J/(kg°C)
dT = .80*½*1.5*3.0²/(1.5*C) = 360/C C°

b)
Remaining energy heats the surface and surrounding air.
1
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