I'm working on some physics homework and #3 is very confusing, I cannot figure out this question, so if anyone can be some assistance, I'll greatly appreciate it.
Here's the problem:An elevator is initially moving upward at a speed of 11.76 m/s. The elevator experiences a constant downward acceleration of magnitude 4.24 m/s2 for 3.03 s.
(a) Find the magnitude and direction of the elevator's final velocity.
I thought about Vaverage = (Vi + Vf)/2 but its' not coming out correctly. :-(
Here's the problem:An elevator is initially moving upward at a speed of 11.76 m/s. The elevator experiences a constant downward acceleration of magnitude 4.24 m/s2 for 3.03 s.
(a) Find the magnitude and direction of the elevator's final velocity.
I thought about Vaverage = (Vi + Vf)/2 but its' not coming out correctly. :-(
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Vf = Vi - a * t
= 11.76 - (4.24 * 3)
= -0.96 m/s ( negative sign indicates downward direction )
= 11.76 - (4.24 * 3)
= -0.96 m/s ( negative sign indicates downward direction )
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****** retards jumped on the ******* damn elevator and broke the piece of ****, v=zer000