A rock stuck in the tread of a 51.0-cm-diameter bicycle wheel has a tangential speed of 3.30 m/s. When the brakes are applied, the rock's tangential deceleration is 1.30 m/s/s .
What is the magnitudes of the rock's angular velocity at t= 1.60 s?
and What is the magnitudes of the rock's angular acceleration at the same time (t= 1.60 s)?
What is the magnitudes of the rock's angular velocity at t= 1.60 s?
and What is the magnitudes of the rock's angular acceleration at the same time (t= 1.60 s)?
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r =0.51m / 2 = 0.255m
r * angular speed w = tangential speed of 3.30
w = 12.94 rad /s
r * angular deceleration= tangential deceleration is 1.30
angular deceleration = 5.098 rad /s2
angular acceleration at the same time (t= 1.60 s)
answer
t =1.6s
v =u +at
v = 12.94 - 5.098 * 1.6 = 4.783 rad/s
answer
angular velocity at t= 1.60 s
r * angular speed w = tangential speed of 3.30
w = 12.94 rad /s
r * angular deceleration= tangential deceleration is 1.30
angular deceleration = 5.098 rad /s2
angular acceleration at the same time (t= 1.60 s)
answer
t =1.6s
v =u +at
v = 12.94 - 5.098 * 1.6 = 4.783 rad/s
answer
angular velocity at t= 1.60 s