Question about applied forces
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Question about applied forces

[From: ] [author: ] [Date: 12-07-01] [Hit: ]
=>mgcosθ = 70.=>cosθ = 0.=>a = 9.=>a = 1.......
A 10.0 kg block is on an inclined plane. If the friction between the block and the plane is 50 N, and the normal force between the block and incline is 70.7 N, what is the acceleration of the block?

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Given N = 70.7
=>mgcosθ = 70.7
=>cosθ = 0.72 = cos44*
=>θ = 44*
By F(net) = F(gravity) - F(friction)
=>m x a = mgsinθ - 50
=>a = 9.8 x sin44* - 5
=>a = 1.81 m/s^2
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