If 0.459 g of NO2 (g) has a volume of 14.2 L and a pressure of 1.75 atm, calculate the temperature of the gas.

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If 0.459 g of NO2 (g) has a volume of 14.2 L and a pressure of 1.75 atm, calculate the temperature of the gas.

[From: ] [author: ] [Date: 11-06-10] [Hit: ]

459 g NO2) / (46.0056 g NO2/mol) = 0.T = PV/nR = (1.75 atm) (14.2 L) / ( 0.009977 mol) (0.......

In kelvin (k). PLEASE. :)

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(0.459 g NO2) / (46.0056 g NO2/mol) = 0.009977 mole NO2

PV = nRT
T = PV/nR = (1.75 atm) (14.2 L) / ( 0.009977 mol) (0.08205746 L atm /K mol) = 30400 degrees K

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