Relation to time math problem

Jim is traveling at an average rate of 55 miles per hour. He began traveling at 10:30 a.m. and will travel a total distance of 248 miles. Jim does not make any stops. At what time should he arrive at his destination? Please explain to me how you got this answer as well.

Speed = distance / time

55 mph = speed
248 miles = distance
t = time

55 = 248/t
55t = 248
t = ~4.509 hours

.509 hours * 60 mins per hour = 31 minutes

So it should take Jim about 4 hours, 31 minutes to reach his destination. Adding this to the time he started, we get that Jim should arrive at about 3:01pm.

Jim goes 55 mph for a distance of 248 miles.

248 mile / 55mph = 4 28/55 hrs =
4 hrs 30 6/11 min

10:30 + 4:30 = 14:60 = 15:00 = 3pm

6/11 min = 360/11 sec = 32 8/11 sec

so 32.7272... sec after 3pm

time required = 248/55 = 4.50909 hours = 4 hours and 30 minutes and 33 seconds
He should arrive at 10:30 + 4h 30m 33 s = 15:00:33 = 3:00:33 pm

time to travel distance
= 248 / 55
= 4.509 hrs
= 4 hours 31 mins

Add 4 hours 31 mins to 10.30 am to get 3.01 pm