38 m/s drops a package of emergency rations from a height of 119 m to a stranded party of explorers. The acceleration of gravity is 9.8 m/s^2.
a) Where does the package strike the ground relative to the point directly below where it was released.
b) What is the horizontal component of the velocity just before it hits?
c) What is the vertical component of the velocity just before it hits?
I have been trying and trying to get the answer and i cant seem to get it right. Can somebody help me with the steps please?
a) Where does the package strike the ground relative to the point directly below where it was released.
b) What is the horizontal component of the velocity just before it hits?
c) What is the vertical component of the velocity just before it hits?
I have been trying and trying to get the answer and i cant seem to get it right. Can somebody help me with the steps please?
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Time to drop 119m. = sqrt. (2h/g), = 4.928 secs.
a) In 4.928 secs., it hits the ground (4.928 x 38) = 187.264m. from release point.
b) It is 38m/sec.
c) Vertical component = (gt), = 9.8 x 4.928, = 48.29m/sec.
a) In 4.928 secs., it hits the ground (4.928 x 38) = 187.264m. from release point.
b) It is 38m/sec.
c) Vertical component = (gt), = 9.8 x 4.928, = 48.29m/sec.