2x-3[x-2(4-x)]=?? please break this down so I can do this simply

please include each step for order of operations

2x - 3[x - 2(4 - x)]

2x - 3[x - 8 + 2x]

2x - 3[3x - 8]

2x - 9x + 24

-7x + 24

[2X-3(X-20)(4-X)}
First; solve (x-2)(4-x)
X times 4, then x times – x
Next, - 2 times 4, then -2 times -x
Answer (4x –x^2 – 8 + 2X)
Simplify this (6x-x^2-8)
Second; 2x-3(6x-x^2-8)
2x-18x+3x^2+24
You final answer is
-16x+3x^2 +24 or 3x^2-16x+24
gets?

2x - 3 [ x - 2 ( 4 - x ) ]

2x - 3 [ x - 8 + 2x]

2x - 3 [ 3x- 8 ]

2x-9x +24

-7x +24

2x-3[(-x^2+6x-8)]
the answer is -2x^3+9x^2+2x+24

2x - 3(x - 2(4 - x))

2x - 3(x - 8 + x)

2x - 3(2x - 8)

2x - 6x + 24

- 4x + 24