I have a quick derivative question

I have one equation X=1/3(2t+1)^3/2
I have found the derivative to be 1/2(2t+1)^1/2
The question then asks me to square the equation and thats where it confuses me.
Would I have square the numbers in the parenthesis (in 2t+1?)
I just want to know the correct way of doing it without making a mistake.
Thanks!

The derivative of X with respect to t is:

X=1/3(2t+1)^3/2

X ' = (3/2)(1/3)(2t+1)^1/2 * 2 = (2t+1)^1/2 [don't forget to use the "chain rule"]

Now square the equation is simply raise it to the second power:

[ (2t+1)^1/2 ] ^2 = 2t + 1

Hope that helps