2 Maths Questions!!!

1) Given that 408 = 2^3*3*17 and 1156 = 2^2*17^2, use the result to find the smallest positive integer value of M for which 408M is a perfect cube.

2) Find the smallest positive integer for N for which 3√1005N*63 is a whole number.

Stuck at these questions. Hope you can help. Thanks

1) Given that 408 = 2^3*3*17 and 1156 = 2^2*17^2, use the result to find the smallest positive integer value of M for which 408M is a perfect cube.
The prime factors of a perfect prime must have each prime factor three times.
408 has only one of it's prime factors three times(ie 2^3)

M must therefore be 3*3*17*17=2601

2) Find the smallest positive integer for N for which 3√1005N*63 is a whole number.
I will assume that what you have typed is the cube root of (1005 * N *63)
1005=5*3*67
63=3*3*7
The smallest N=5*5*7*7*67*67=5499025

What is M,N and how to understand 408M?
408M is 408*M or if e.g. M=91 the number is 40891 ?